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Class 12 Chemistry · Chapter 6 · Organic Chemistry 🔴 Hard

Haloalkanes and Haloarenes

From the chloroform in old medicines to the CFCs that damaged the ozone layer — the chemistry of organic halides. With interactive SN1 vs SN2 comparison, mechanism diagrams, stereochemistry, and 20+ real-life examples.

⏱️ ~45 min read · 📚 9 sections · 🧮 2 interactive tools · 🎯 7 solved + 10 NCERT
9Sections
20+Real-life Examples
10Reaction Diagrams
2Interactive Tools
18MCQs
The Big Picture

🗺️ How Everything Connects

Before diving in, here's the entire chapter on one page. From classification → preparation → reactions via SN1/SN2 → haloarenes → environmental effects.

Classify + Name C-X Bond Nature Preparation Methods SN1 vs SN2 Elimination E1/E2 Haloarenes + Env. Grignard Ozone Depletion "How does the C-X bond determine reactivity, stereochemistry, and mechanism?" C-X bond polarity → nucleophilic substitution. Steric/electronic effects → SN1 or SN2
Key Takeaway

Haloalkanes (R-X) and haloarenes (Ar-X) are organic compounds with halogen atoms. The polar C-X bond makes them reactive toward nucleophiles. SN1 vs SN2 depends on substrate, nucleophile, solvent, and leaving group. Haloarenes are much less reactive to nucleophilic substitution (partial double bond character of C-X). Environmental concerns: CFCs deplete ozone; DDT is banned for bioaccumulation.

Section 01

Classification of Haloalkanes & Haloarenes

6.1Types of Organic Halides

Basic Definitions

Haloalkanes (Alkyl halides, R-X): Halogen attached to sp³ hybridized carbon of an alkyl group.

Haloarenes (Aryl halides, Ar-X): Halogen attached directly to sp² hybridized carbon of an aromatic ring.

Allylic halides: Halogen on sp³ carbon adjacent to a C=C double bond.

Benzylic halides: Halogen on sp³ carbon adjacent to an aromatic ring.

Vinylic halides: Halogen on sp² carbon of a C=C double bond.

Aryl halides: Halogen on sp² carbon of an aromatic ring.

Type Example Reactivity to Nucleophilic Substitution
Alkyl halide (primary) CH₃-CH₂-Cl High (SN2 favorable)
Alkyl halide (tertiary) (CH₃)₃C-Cl High (SN1 favorable)
Allylic halide CH₂=CH-CH₂-Cl Very high (allylic stabilization)
Benzylic halide Ph-CH₂-Cl Very high (benzylic stabilization)
Vinylic halide CH₂=CH-Cl Very low (partial double bond)
Aryl halide Ph-Cl (chlorobenzene) Very low (partial double bond)
Classification by Number of Halogen Atoms
  • Mono — one halogen (CH₃Cl)
  • Di — two halogens (CH₂Cl₂, dichloromethane)
  • Tri — three halogens (CHCl₃, chloroform)
  • Tetra — four halogens (CCl₄, carbon tetrachloride)
  • Poly — many halogens (e.g., CFCs)
Primary, Secondary, Tertiary (for Haloalkanes)
  • Primary (1°): Halogen on carbon bonded to 1 other carbon. R-CH₂-X
  • Secondary (2°): Halogen on carbon bonded to 2 other carbons. R₂CH-X
  • Tertiary (3°): Halogen on carbon bonded to 3 other carbons. R₃C-X
Real Life Connect
  • CH₂=CH-Cl (vinyl chloride): Monomer for PVC plastic
  • Ph-CH₂-Cl (benzyl chloride): Used in organic synthesis (benzyl group added easily)
  • Cl-CH₂-CH₂-Cl (ethylene dichloride): Precursor to vinyl chloride and PVC
  • DDT: p,p'-dichlorodiphenyltrichloroethane — banned pesticide
  • Chlorobenzene: Solvent, precursor to phenol
  • Halothane (CF₃-CHClBr): Anesthetic
Key Takeaway

Haloalkanes = R-X (sp³ C). Haloarenes = Ar-X (sp² C). Allylic and benzylic are highly reactive; vinylic and aryl are very unreactive. Classification: 1°/2°/3° (haloalkanes), mono/di/tri/poly (by count), and by position (allylic, benzylic, vinylic).

Section 02

IUPAC Nomenclature

6.2Naming Rules

IUPAC Rules

Rule 1 — Haloalkanes (R-X):

  • Name as halo- + alkane with chain including the carbon attached to X.
  • Halogens = fluoro, chloro, bromo, iodo (as prefix).
  • Prefix in alphabetical order if multiple halogens.

Example: CH₃-CH₂-Cl = chloroethane (common: ethyl chloride)

Example: CH₃-CH(Cl)-CH₃ = 2-chloropropane (isopropyl chloride)

Example: CH₂Cl₂ = dichloromethane

Example: CHCl₃ = trichloromethane (chloroform)

Example: CCl₄ = tetrachloromethane (carbon tetrachloride)

Example: CH₃-CH(Br)-CH₂-Cl = 1-bromo-2-chloropropane (alphabetical: bromo before chloro)

Rule 2 — Haloarenes (Ar-X):

  • Name as halo- + benzene or as substituent on the aromatic ring.

Example: Ph-Cl = chlorobenzene

Example: Ph-Br = bromobenzene

Example: 1,2-dichlorobenzene (or ortho-dichlorobenzene)

Example: 2-chloro-4-nitrotoluene (positional with respect to methyl)

Rule 3 — Allylic and Benzylic:

Example: CH₂=CH-CH₂-Br = 3-bromoprop-1-ene

Example: Ph-CH₂-Cl = (chloromethyl)benzene or benzyl chloride

Rule 4 — Vinylic and Aryl (halogen on sp² carbon):

Example: CH₂=CH-Cl = chloroethene (vinyl chloride)

Common vs IUPAC Names
Common Name IUPAC Name Formula
Methyl chloride Chloromethane CH₃Cl
Ethyl chloride Chloroethane C₂H₅Cl
Isopropyl chloride 2-Chloropropane CH₃CHClCH₃
t-Butyl chloride 2-Chloro-2-methylpropane (CH₃)₃CCl
Methylene chloride Dichloromethane CH₂Cl₂
Chloroform Trichloromethane CHCl₃
Carbon tetrachloride Tetrachloromethane CCl₄
Vinyl chloride Chloroethene CH₂=CHCl
Allyl bromide 3-Bromoprop-1-ene CH₂=CHCH₂Br
Benzyl chloride Chloromethylbenzene C₆H₅CH₂Cl
Chlorobenzene Chlorobenzene C₆H₅Cl
Common Mistake

Mistake: "Halogen is always given the lowest locant."
Correction: Halogens are treated as substituents, not the principal functional group. If another group (like -OH, -COOH) is present, that determines numbering. Halogens just get whatever locants result. Example: CH₂Cl-CH₂-OH = 2-chloroethanol (OH gets priority, numbered 1).

Key Takeaway

IUPAC names: halo- prefix + alkane/benzene. Haloalkanes: longest chain includes C-X. Prefixes in alphabetical order. Halogens are substituents (lowest priority). Common names still widely used (ethyl chloride, chloroform).

Section 03

Nature of C-X Bond

6.3Polarity and Its Consequences

Polar C-X Bond

The C-X bond is polar because the halogen is more electronegative than carbon. Electronegativity order:

F (4.0) > Cl (3.0) > Br (2.8) > I (2.5) > C (2.5)

So the carbon is δ+ (electrophilic) and halogen is δ− (nucleophilic).

This polarity makes the carbon susceptible to attack by nucleophiles → nucleophilic substitution reactions.

Bond Strength (Bond Dissociation Enthalpy)
Bond BDE (kJ/mol) Reactivity (C-X bond cleavage)
C-F ~485 Very low (strongest bond)
C-Cl ~327 Moderate (most used in reactions)
C-Br ~285 High
C-I ~213 Very high (weakest bond, best leaving group)

Reactivity order: R-I > R-Br > R-Cl > R-F (for C-X bond cleavage)

Why? Longer, weaker bonds break more easily. The iodide ion is also a better leaving group (larger, more polarizable, more stable anion).

C-X Bond in Haloarenes

In aryl halides (Ar-X), the C-X bond has partial double bond character due to resonance (lone pair on X donates into the ring). This makes the C-X bond shorter and stronger than in alkyl halides.

Consequences:

  • Haloarenes are very unreactive to nucleophilic substitution
  • The C-Cl bond in chlorobenzene is shorter (1.69 Å) than in chloroethane (1.79 Å)
  • Requires forcing conditions for substitution (high T, high P)
  • But haloarenes are easily attacked by electrophiles (ring substitution)
Why Is C-I the Best Leaving Group?

I⁻ is the weakest base among halide ions (conjugate base of strongest acid HI), so it's most stable as a free anion. It's also the largest ion (most polarizable), so the C-I bond is longest and weakest. Both factors → I⁻ leaves most easily → C-I most reactive to substitution.

Real Life Connect
  • Alkyl iodides: Used in radiolabeling (¹²³I, ¹³¹I for imaging/thyroid)
  • Alkyl bromides: Common in organic synthesis (better leaving group than Cl, cheaper than I)
  • Alkyl chlorides: Industrial scale (chloroform, CCl₄, PVC)
  • Fluorocarbons (C-F): Extremely stable — used as refrigerants (CFCs, replaced by HFCs)
  • Chlorobenzene: Industrial solvent, less reactive but useful for aromatic chemistry
Key Takeaway

C-X bond is polar (C is δ+, X is δ−). Halogen more electronegative → nucleophilic attack on carbon. Reactivity: R-I > R-Br > R-Cl > R-F (weaker C-X = better leaving group). Haloarenes: C-X has partial double bond character → very unreactive.

Section 04

Methods of Preparation

6.4Synthesis Routes

1. From Alcohols

Using HX:

R-OH + HX → R-X + H₂O

Order of reactivity: HI > HBr > HCl > HF (HCl needs ZnCl₂ catalyst for primary/secondary alcohols)

3° alcohol + HCl (room temp) → 3° alkyl chloride (no catalyst needed)

1° alcohol + HCl (anhydrous ZnCl₂) → 1° alkyl chloride (Lucas test)

Using PCl₃, PCl₅, SOCl₂:

3R-OH + PCl₃ → 3R-Cl + H₃PO₃

R-OH + PCl₅ → R-Cl + POCl₃ + HCl

R-OH + SOCl₂ → R-Cl + SO₂ + HCl (SOCl₂ = thionyl chloride — best for clean reaction, no side products)

2. From Hydrocarbons

Alkanes (free radical halogenation):

R-H + X₂ → R-X + HX (in presence of UV light or heat)

Order of reactivity of halogens: F₂ > Cl₂ > Br₂ > I₂ (I₂ reversible, so rarely used)

For alkanes with multiple types of H, order of substitution: 3° > 2° > 1° (due to radical stability)

Alkenes (addition of HX):

CH₂=CH₂ + HCl → CH₃-CH₂-Cl

Markovnikov's rule: H adds to carbon with more H, X to other carbon

Anti-Markovnikov (peroxides): HBr + alkene + peroxide → anti-Markovnikov alkyl bromide (only for HBr)

Alkynes (addition):

CH≡CH + HCl → CH₂=CH-Cl (vinyl chloride)

CH≡CH + 2HCl → CH₃-CHCl₂ (ethylidene dichloride)

3. Halogen Exchange (Finkelstein & Swarts)

Finkelstein reaction: R-X + NaI → R-I + NaX (X = Cl, Br)

In dry acetone, NaCl/NaBr precipitate out, driving forward to R-I.

Swarts reaction: R-X + AgF → R-F + AgX (X = Cl, Br, I)

Or: R-X + Hg₂F₂ → R-F + Hg₂X₂ (for making alkyl fluorides)

4. From Haloarenes (Haloarenes)

Sandmeyer reaction:

Ar-N₂⁺Cl⁻ + Cu₂Cl₂/HCl → Ar-Cl + N₂

Or with Cu₂Br₂/HBr → Ar-Br

Uses diazonium salt from aniline → various aryl halides.

Balz-Schiemann reaction (for Ar-F):

Ar-N₂⁺BF₄⁻ → Ar-F + N₂ + BF₃ (on heating)

Direct halogenation of arene:

Benzene + Cl₂ --(FeCl₃)--> chlorobenzene

Benzene + Br₂ --(FeBr₃)--> bromobenzene

Real Life Connect
  • Chloroform: Prepared by treating ethanol/acetone with bleaching powder (industrial scale)
  • CCl₄: From CS₂ + Cl₂ (historical) or from methane + Cl₂
  • Vinyl chloride: From ethene + Cl₂ → 1,2-dichloroethane → pyrolysis → vinyl chloride (PVC precursor)
  • Haloarenes: From benzene + halogen (FeCl₃ catalyst) — Sandmeyer reaction for less reactive positions
Key Takeaway

Main methods: (1) Alcohol + HX/PCl₃/PCl₅/SOCl₂ → R-X. (2) Alkane/alkene/alkyne + halogen → R-X (free radical or addition). (3) Halogen exchange (Finkelstein for iodides, Swarts for fluorides). (4) Haloarenes from Sandmeyer/Balz-Schiemann reaction from diazonium salts.

Section 05

Physical Properties

6.5Physical Behaviour

Melting and Boiling Points

Boiling points:

  • Increase with molecular mass (larger = more London dispersion forces)
  • Order: R-I > R-Br > R-Cl > R-F
  • Branching decreases boiling point (less surface area)
  • R-Br > R-Cl > R-F for same R (Br and I have more electrons)

Melting points:

  • Show odd-even effect (even carbon chain packs better in crystals → higher MP)
  • Also increase with mass, decrease with branching
Solubility

In water: Haloalkanes are only slightly soluble in water because:

  • They don't form H-bonds (no -OH or -NH)
  • They cannot break water's strong H-bond network

However, they dissolve in organic solvents (ether, benzene, alcohols) because London dispersion forces dominate.

Density
  • Haloalkanes with multiple halogens or heavier halogens are denser than water (sp. gravity > 1)
  • Fluorides (C-F) may be less dense than water
  • Bromo and iodo compounds are especially dense (Br, I are heavy)
  • Example: CHCl₃ (chloroform) density 1.49 g/mL — sinks in water
  • Example: CCl₄ density 1.59 g/mL — sinks in water
Colour and Odour
  • Most are colourless
  • CH₃I is violet (decomposes to I₂ on exposure to light)
  • Most have sweet, characteristic smells (chloroform — sweet, ether-like)
Real Life Connect
  • Chloroform (1.49 g/mL): Sinks in water — old trick to distinguish from alcohol
  • CCl₄ (1.59 g/mL): Used as fire extinguisher (dense liquid smothers flames)
  • CH₃I: Decomposes on exposure to light (store in amber bottles)
  • Bromo derivatives: Higher density — used in flame retardants
  • Fréons (CFCs): Low BP, non-toxic, ideal refrigerants (but environmentally harmful)
Key Takeaway

Boiling points: R-I > R-Br > R-Cl > R-F (mass effect). Branching decreases BP and MP. Slightly soluble in water (no H-bond), very soluble in organics. Heavier halogens → denser than water. Mostly colourless with characteristic odours.

Section 06

Nucleophilic Substitution — SN1 vs SN2

6.6The Two Competing Pathways

General Reaction

R-X + Nu⁻ → R-Nu + X⁻

Nucleophile (Nu⁻) replaces the halogen (X⁻, leaving group).

SN2 — Bimolecular Nucleophilic Substitution

Rate law: Rate = k[R-X][Nu⁻] (second-order kinetics)

Mechanism: ONE step — Nu⁻ attacks the carbon from the backside (opposite the leaving group), displacing X⁻ simultaneously.

Stereochemistry: Inversion of configuration (Walden inversion) — like an umbrella turning inside-out.

Favored by:

  • Primary (1°) alkyl halides — less steric hindrance
  • Strong nucleophiles (CN⁻, I⁻, HS⁻, R₃P)
  • Polar aprotic solvents (DMSO, DMF, acetone) — don't H-bond to Nu⁻
  • Better leaving groups (I⁻ > Br⁻ > Cl⁻ > F⁻)
SN1 — Unimolecular Nucleophilic Substitution

Rate law: Rate = k[R-X] (first-order kinetics)

Mechanism: TWO steps —

  1. Slow (rate-determining): C-X bond breaks, forming a carbocation (R⁺) + X⁻
  2. Fast: Nu⁻ attacks the carbocation

Stereochemistry: Racemic mixture (both d and l forms) — because carbocation is planar, Nu⁻ can attack from either face with equal probability.

Favored by:

  • Tertiary (3°) alkyl halides — stable carbocation (more alkyl substitution)
  • Weak nucleophiles (H₂O, ROH)
  • Polar protic solvents (H₂O, ROH) — solvate carbocation
  • Better leaving groups
  • Rearrangement can occur (carbocation can rearrange to more stable one)
V1 · SN2 vs SN1 mechanism SN2 — One Step, Inversion Start C R₁ R₂ R₃ Br Nu⁻ Nu approaches from back Transition state C Nu Br 5-coordinate, planar-ish, partial bonds Final (inverted) C Nu Walden inversion (like umbrella flip) SN1 — Two Steps, Racemization Start C Br Step 1 (slow): Carbocation forms C⁺ Br⁻ Planar carbocation → attack from either face Step 2 (fast): Racemic mixture C Nu 50% d-form C Nu 50% l-form

SN1 vs SN2 Predictor

Choose substrate, nucleophile, and solvent — predict the mechanism.

Mechanism
—
Stereochemistry
—
Rate Law
—
Notes
—
Feature SN1 SN2
Kinetics Rate = k[R-X] (first-order) Rate = k[R-X][Nu⁻] (second-order)
Steps 2 (carbocation intermediate) 1 (concerted)
Stereochemistry Racemic mixture Inversion (Walden)
Favored substrate 3° > 2° > 1° (carbocation stability) 1° > 2° > 3° (steric hindrance)
Solvent Polar protic (H₂O, ROH) Polar aprotic (DMSO, DMF, acetone)
Nucleophile Weak (H₂O, ROH) Strong (CN⁻, I⁻)
Rearrangement Possible (carbocation) No
Leaving group Better = faster Better = faster
Analogy

SN2 is like replacing a passenger in a moving car: The new passenger (Nu⁻) can only get in if they simultaneously push the old one (X⁻) out the other door — one smooth motion. Steric crowding inside (branching) makes it harder for new passenger to get in.

SN1 is like a passenger jumping out first: The old passenger (X⁻) leaves the car (slow step), then the new one (Nu⁻) gets in from any side (fast step). Faster if the car seat is roomy (stable carbocation).

Key Takeaway

SN2 = 1 step, second-order, inversion, favored by 1° + strong Nu + aprotic solvent. SN1 = 2 steps via carbocation, first-order, racemic, favored by 3° + weak Nu + protic solvent. Allylic/benzylic are reactive via both mechanisms. Aryl/vinylic are unreactive.

Section 07

Elimination Reactions (E1, E2)

6.7Competing with Substitution

Elimination Reactions

Elimination: Removal of HX from alkyl halide → alkene.

General: R-CH₂-CH₂-X + Base → R-CH=CH₂ + HX

Elimination competes with substitution when using strong bases (e.g., KOH in ethanol, t-BuOK).

E1 — Unimolecular Elimination

Rate law: Rate = k[R-X] (first-order)

Mechanism: 2 steps

  1. Slow: C-X bond breaks → carbocation
  2. Fast: Base abstracts β-H → alkene

Favored by: 3° alkyl halides, weak base, polar protic solvent

Regiochemistry: Zaitsev's rule — more substituted alkene favored (more stable)

E2 — Bimolecular Elimination

Rate law: Rate = k[R-X][Base] (second-order)

Mechanism: 1 step — base attacks β-H while C-X bond breaks → alkene forms

Favored by: 1° and 2° alkyl halides, strong bulky base (t-BuOK), high T

Regiochemistry: Zaitsev's rule (more substituted alkene) for small bases; Hofmann product (less substituted) for bulky bases (t-BuOK)

Stereochemistry: Anti-periplanar geometry required (H and X must be on opposite sides)

Feature E1 E2
Kinetics First-order Second-order
Steps 2 (carbocation) 1 (concerted)
Favored substrate 3° > 2° > 1° 2° > 1° (3° gives mostly E2 but can be tricky)
Base Weak Strong (bulky = Hofmann)
Solvent Polar protic Often polar aprotic
Regiochemistry Zaitsev (more stable alkene) Zaitsev (small base) or Hofmann (bulky base)
Stereochemistry Not strict Anti-periplanar
Substitution vs Elimination

The outcome depends on:

  • Base strength: Strong base → more E2
  • Bulky base: t-BuOK → favors Hofmann (least substituted alkene) but E2 dominant
  • Nucleophile strength: Strong Nu → more SN2
  • Temperature: Higher T favors elimination (ΔS effect)
  • Substrate: 1° → SN2 (or E2 with strong base); 3° → SN1/E1 (or E2 with strong base)
Real Life Connect
  • Alkene production: E1/E2 is used industrially to make alkenes from alkyl halides
  • t-BuOK vs NaOH: Selective bases give different products
  • Cracking in petroleum: Alkanes → alkenes + H₂ (thermal elimination)
  • Drug synthesis: Careful control of elimination for specific alkenes
Key Takeaway

E1 = carbocation intermediate, 2 steps, first-order, weak base. E2 = concerted, 1 step, second-order, strong base. Zaitsev's rule → more substituted alkene (small bases). Hofmann product → less substituted (bulky bases like t-BuOK). Substitution competes with elimination.

Section 08

Reactions of Haloarenes

6.8Special Reactivity of Aryl Halides

Why Are Haloarenes Unreactive to Nucleophilic Substitution?

Three reasons:

  1. Partial double bond character: Lone pair on X resonates into the ring → C-X bond shorter and stronger (like a double bond)
  2. sp² hybridization: Carbon is sp² (more s-character) → bonds to X are stronger and shorter
  3. Electron-rich ring: Repels incoming nucleophile

Result: Haloarenes require forcing conditions for nucleophilic substitution (high T, high P, strong Nu).

Nucleophilic Substitution of Haloarenes (Dow Process)

Chlorobenzene + NaOH (300°C, 300 atm) → phenol

Requires extreme conditions — impossible under normal lab conditions.

However: If electron-withdrawing groups (NO₂, CN, etc.) are present on the ring (ortho or para to X), the reaction becomes much easier.

Example: 2,4,6-trinitrochlorobenzene + H₂O (room temp) → picric acid (fast — no forcing conditions!)

Reason: -NO₂ stabilizes the anionic intermediate (Meisenheimer complex) via resonance.

Reactions of Haloarenes

1. Electrophilic substitution (ring reactions):

Halogen is ortho/para directing (due to resonance donation) but deactivating (due to inductive withdrawal).

Example: chlorobenzene + Cl₂/FeCl₃ → 1,4-dichlorobenzene (para major)

2. Formation of Grignard reagent:

Ar-Br + Mg/dry ether → Ar-MgBr

Does NOT work for Ar-Cl or Ar-F (bond too strong). Works for Ar-I (very reactive) and Ar-Br (moderate).

3. Wurtz-Fittig reaction:

Ar-X + R-X + 2Na/dry ether → Ar-R + 2NaX

Forms alkylarene.

4. Fittig reaction:

2Ar-X + 2Na/dry ether → Ar-Ar + 2NaX

Forms biphenyl.

5. Reduction:

Ar-X + Zn/HCl → Ar-H + HX (rare; usually not done this way)

6. Friedel-Crafts acylation (limited):

Ar-X can be acylation substrate but reactivity is low; use AlCl₃ catalyst.

Real Life Connect
  • Chlorobenzene: Solvent, precursor to phenol, DDT, some drugs
  • Bromobenzene: Grignard precursor for phenyl group additions
  • Fluorobenzene: Intermediate in agrochemical synthesis
  • Trinitrochlorobenzene: Explosive precursor (picric acid)
  • Chlorinated benzenes: PCBs (polychlorinated biphenyls) — banned pollutants
Key Takeaway

Haloarenes are unreactive to nucleophilic substitution (partial double bond, sp² C, electron-rich ring). Requires Dow process conditions (300°C, 300 atm) unless electron-withdrawing groups (NO₂, CN) are present. Reactive to electrophilic substitution (ring position). Grignard works only for Ar-I and Ar-Br.

Section 09

Polyhalogen Compounds

6.9Chloroform, CCl₄, DDT, CFCs

Chloroform (CHCl₃)

Preparation: From ethanol/acetone + bleaching powder

2CH₃CH₂OH + 4Cl₂ + Ca(OH)₂ → 2CHCl₃ + (HCOO)₂Ca + CaCl₂ + 4H₂O (simplified)

Properties:

  • Sweet-smelling, non-flammable, dense liquid (1.49 g/mL)
  • Good solvent for fats, oils, resins, rubber, etc.
  • Historically used as anesthetic (but toxic — causes liver/kidney damage)
  • Decomposes on exposure to air/light → phosgene (COCl₂, highly toxic) and Cl₂
  • Stored in dark bottles with 1% ethanol (ethanol traps phosgene)

Uses: Solvent, precursor for chlorodifluoromethane (CFC-22), in cough syrups (trace), precursor to other chemicals.

Carbon Tetrachloride (CCl₄)

Preparation: From methane + chlorine (free radical substitution), or from CS₂ + Cl₂

Properties:

  • Non-flammable, dense (1.59 g/mL), sweet-smelling
  • Excellent solvent for fats, oils, resins
  • Toxic — causes liver damage (though less than chloroform)
  • Depletes ozone layer (banned by Montreal Protocol)

Uses: Fire extinguishers (Pyrene), solvent, precursor for CFCs (before ban).

Freons (CFCs)

Freon-12 (CCl₂F₂, dichlorodifluoromethane): Common refrigerant, propellant.

Properties: Non-toxic, non-flammable, easily liquefied, chemically inert.

BUT: Extremely harmful to ozone layer — depletes ozone via radical chain reaction:

CFCl₃ --(UV)--> CFCl₂· + Cl·

Cl· + O₃ → ClO· + O₂

ClO· + O· → Cl· + O₂ (Cl is regenerated — 1 Cl destroys thousands of O₃ molecules)

Result: Montreal Protocol (1987) — worldwide ban on CFCs. Replaced by HFCs (less ozone-depleting, but greenhouse gases).

DDT (p,p'-dichlorodiphenyltrichloroethane)

Structure: Two para-chlorophenyl rings + CCl₃ group on the same carbon.

Use: Powerful insecticide — kills mosquitoes (malaria), lice (typhus), etc.

Problems:

  • Bioaccumulation: Fat-soluble, not metabolized → accumulates in fatty tissue
  • Biomagnification: Concentration increases up the food chain (banned for agriculture in most countries)
  • Harmful to birds (eggshell thinning — nearly caused bald eagle extinction)
  • Persistent in environment (very slow degradation)

Banned in agriculture globally (Stockholm Convention, 2001), but still used for mosquito control in some regions (WHO approved for malaria).

Real Life Connect
  • Chloroform: Historically used as anesthetic (1847-1930s); now banned in many places due to toxicity
  • DDT: Banned in US/Europe for agriculture; still WHO-approved for malaria control in Africa
  • CFCs: Montreal Protocol phased out all CFCs by 2010 (developed countries) / 2016 (India)
  • Ozone hole: Discovered 1985 over Antarctica — directly linked to CFCs
  • Phosgene: Used as chemical weapon in WWI; unintentional by-product of chloroform decomposition
Did You Know?

The Montreal Protocol is considered the most successful international environmental treaty — the ozone layer is now recovering and expected to be fully healed by 2066. HFCs (replacement for CFCs) don't deplete ozone but are potent greenhouse gases — being phased out under the Kigali Amendment (2016).

Key Takeaway

Chloroform: solvent, anaesthetic (historical), toxic (phosgene). CCl₄: solvent, fire extinguisher, ozone depleter (banned). CFCs: refrigerants, cause ozone depletion (Montreal Protocol). DDT: insecticide, bioaccumulates (banned globally for agriculture). Environmental awareness critical for organic chemistry applications.

Memory Aids

🧠 Mnemonics & Memory Tricks

🎯 Chapter-Wide Memory Aids

SN1 vs SN2

"SN1 = 1 molecule, 1 rate, 1 step, 1° NO"

SN1 = first-order, 2 steps, racemic. SN2 = second-order, 1 step, inversion.

"1° Substrate → SN2, 3° Substrate → SN1"

Remember: "Primary Substitutes 2, Tertiary Substitutes 1" (PS2, TS1)

Reactivity of Halides

"I > Br > Cl > F" (I is best leaving group — weakest base, largest ion)

Remember: "Iodide Iodizes, Bromide Brominates, Chloride Chlorinates, Fluoride Fails"

Zaitsev vs Hofmann

"Zaitsev Zaps to Z-most" — Zaitsev (small base) → more substituted alkene (most stable).

"Bulky Bases Buck the Trend" — Hofmann (t-BuOK) → less substituted alkene.

Finkelstein vs Swarts

"Finkelstein is Fine for Iodide" — R-X + NaI → R-I (dry acetone).

"Swarts uses Silver for Fluoride" — R-X + AgF → R-F.

CFC Ozone Destruction

"Cl· + O₃ → ClO· + O₂ → Cl regenerated"

One chlorine atom destroys ~100,000 ozone molecules before being removed.

DDT Bioaccumulation

"DDT — Fat-Soluble Fatale" — accumulates in fat, magnifies up food chain, kills predators.

Haloarene Reactivity

"Double Bond, Double Trouble" — C-X partial double bond makes haloarenes unreactive to nucleophilic substitution.

"NO₂ = Now Reaction Possible" — electron-withdrawing groups (ortho/para) increase reactivity.

Markovnikov's Rule

"H goes to H-rich carbon" — H adds to carbon with more hydrogens.

Exception: HBr with peroxide → anti-Markovnikov (only for HBr).

Key Takeaway

Use "I>Br>Cl>F" for leaving groups, "1° SN2 / 3° SN1" for mechanism choice, "Zaitsev = Z-most" for alkene regiochemistry, and "Cl· destroys thousands of O₃" for ozone depletion.

Practice

📝 Solved Examples

📋 2 Marks

Q1. Name the following: (a) CH₃-CH(Br)-CH₂-CH₃, (b) (CH₃)₃C-Cl

(a)

4-carbon chain with Br on carbon 2 → 2-bromobutane

(b)

Central C with 3 methyls + Cl → 2-chloro-2-methylpropane (t-butyl chloride)

(a) 2-Bromobutane; (b) 2-Chloro-2-methylpropane
📋 2 Marks

Q2. Why is haloarene (chlorobenzene) less reactive than haloalkane (chloroethane) toward nucleophilic substitution?

Partial double bond

In chlorobenzene, lone pair on Cl resonates into the ring → C-Cl bond has partial double bond character → shorter, stronger, harder to break.

sp² carbon

Carbon is sp² (more s-character) → C-Cl bond is stronger. In chloroethane, carbon is sp³ (weaker bond).

Haloarene has stronger C-X bond due to resonance and sp² carbon.
📋 3 Marks

Q3. Predict the major product when 2-bromobutane reacts with KOH in aqueous vs alcoholic solution.

KOH (aq)

Nucleophilic substitution (SN2, 2° substrate with strong Nu) → 2-butanol (major product)

CH₃-CH(Br)-CH₂-CH₃ + KOH(aq) → CH₃-CH(OH)-CH₂-CH₃

KOH (alc)

Elimination (E2) → alkenes. Zaitsev product (more substituted) is major.

CH₃-CH(Br)-CH₂-CH₃ + KOH(alc) → CH₃-CH=CH-CH₃ (2-butene, major) + CH₃-CH₂-CH=CH₂ (1-butene, minor)

Reason

In aqueous solution, OH⁻ is a good Nu for substitution (H₂O solvates carbocation poorly, so SN2 dominates for 2°). In alcoholic solution, OH⁻ acts more as base → E2.

Aqueous: 2-butanol. Alcoholic: 2-butene (major) + 1-butene (minor).
📋 3 Marks

Q4. (a) What is Finkelstein reaction? (b) What is Swarts reaction? Give one example each.

Finkelstein reaction

R-X + NaI (dry acetone) → R-I + NaX (X = Cl, Br)

NaCl/NaBr precipitate out in dry acetone, driving the reaction forward. Used to make alkyl iodides.

Swarts reaction

R-X + AgF → R-F + AgX (or use Hg₂F₂, CoF₃)

Used to make alkyl fluorides (Finkelstein doesn't work for F because NaF is soluble in acetone).

Applications

Finkelstein: alkyl iodides for radiolabeling. Swarts: fluorocarbons for refrigerants.

Both are halogen exchange reactions, used for making specific alkyl halides.
📋 5 Marks

Q5. Compare SN1 and SN2 mechanisms with respect to: kinetics, stereochemistry, effect of substrate, solvent, and nucleophile.

Kinetics 1 Mark

SN1: Rate = k[R-X] (first-order). SN2: Rate = k[R-X][Nu⁻] (second-order).

Stereochemistry 1 Mark

SN1: Racemic (carbocation planar, attacked from either face). SN2: Inversion (Walden inversion, backside attack).

Substrate 1 Mark

SN1: 3° > 2° > 1° (carbocation stability). SN2: 1° > 2° > 3° (steric hindrance).

Solvent 1 Mark

SN1: Polar protic (H₂O, ROH) — stabilizes carbocation. SN2: Polar aprotic (DMSO, DMF, acetone) — leaves Nu⁻ free.

Nucleophile 1 Mark

SN1: Weak (H₂O, ROH) — doesn't participate in rate-determining step. SN2: Strong (CN⁻, I⁻) — directly attacks in the single step.

SN1: 2 steps, racemic, 3°, protic. SN2: 1 step, inverted, 1°, aprotic.
📋 5 Marks

Q6. (a) What are CFCs? (b) How do they deplete the ozone layer? (c) What is the Montreal Protocol?

(a) CFCs 1 Mark

Chlorofluorocarbons — compounds with both Cl and F on the same carbon. Example: CFC-12 (CCl₂F₂, Freon-12). Used as refrigerants, propellants, blowing agents.

(b) Ozone depletion 2 Marks

In the stratosphere, UV light breaks CFC:

CCl₂F₂ --(UV)--> CClF₂· + Cl·

Chlorine radical destroys ozone:

Cl· + O₃ → ClO· + O₂

ClO· + O· → Cl· + O₂ (Cl regenerated!)

One Cl atom can destroy ~10⁵ ozone molecules before being removed (by CH₄ or other species).

(c) Montreal Protocol 2 Marks

International treaty signed in 1987 to phase out CFCs and other ozone-depleting substances. Ratified by all 197 UN members. Phase-out completed by 2010 (developed countries) and 2016 (India). Success: ozone layer is recovering — expected to heal by 2066.

CFCs → UV → Cl radical → destroys thousands of O₃ → Montreal Protocol (1987) banned them.
📋 5 Marks

Q7. Predict the products: (a) CH₃CH₂CH₂Cl + KOH (alc), (b) (CH₃)₃CBr + H₂O, (c) Ph-Cl + NaOH (300°C, 300 atm)

(a) 1-chloropropane + KOH(alc) 1½ Marks

1° alkyl halide + strong base → E2 elimination. Product: propene (CH₃-CH=CH₂). Only one alkene possible.

(b) t-butyl bromide + H₂O 1½ Marks

3° alkyl halide + weak nucleophile (H₂O) → SN1. Carbocation forms (t-Bu⁺ is very stable), then H₂O attacks → t-butanol (2-methyl-2-propanol).

(c) Chlorobenzene + NaOH (300°C, 300 atm) 2 Marks

Dow process — nucleophilic aromatic substitution under forcing conditions. Product: sodium phenoxide, then acidification gives phenol. Requires extreme T and P because of partial double bond character.

(a) Propene; (b) t-butanol; (c) phenol (Dow process)
NCERT Textbook

📚 NCERT Exercise Questions

Selected exercise questions from NCERT Class 12 Chemistry Chapter 6. Click each to reveal the solution.

NCERT 6.1
Write structures of the following compounds: (a) 2-chloro-3-methylpentane, (b) 1-chloro-4-ethylcyclohexane, (c) 4-tert-butyl-3-iodoheptane, (d) 1,4-dibromobut-2-ene.
Show Solution

(a) 2-chloro-3-methylpentane: 5-carbon chain (pentane). Cl on C2, methyl on C3.

CH₃-CH(Cl)-CH(CH₃)-CH₂-CH₃

(b) 1-chloro-4-ethylcyclohexane: Cyclohexane ring, Cl on C1, ethyl on C4. Para-arrangement.

(c) 4-tert-butyl-3-iodoheptane: 7-carbon chain. I on C3, t-butyl on C4.

CH₃-CH₂-CH(I)-CH(C(CH₃)₃)-CH₂-CH₂-CH₃

(d) 1,4-dibromobut-2-ene: 4-carbon chain with double bond at C2, Br on C1 and C4.

Br-CH₂-CH=CH-CH₂-Br

NCERT 6.2
Why is sulphuric acid not used during the reaction of alcohols with KI?
Show Solution

Answer: H₂SO₄ oxidizes the iodide ions to I₂:

2KI + H₂SO₄ → 2HI + K₂SO₄

Then HI (or KI) is oxidized by H₂SO₄:

2HI + H₂SO₄ → I₂ + SO₂ + 2H₂O

So instead of getting R-I (which requires KI as nucleophile), we get I₂. The alcohol is wasted. Instead, use H₃PO₄ or dry HCl for iodination via Finkelstein-type reaction.

NCERT 6.3
Write the structures of the major products formed when the following compounds are treated with sodium methoxide (CH₃ONa): (a) 1-bromopentane, (b) 2-bromopentane, (c) 2-bromo-2-methylbutane.
Show Solution

(a) 1-bromopentane: 1° substrate → SN2 → 1-methoxypentane (CH₃-CH₂-CH₂-CH₂-CH₂-OCH₃)

(b) 2-bromopentane: 2° substrate, strong Nu → SN2 and E2 compete. Major = substitution (2-methoxypentane) + elimination (2-pentene and 1-pentene). Both possible.

(c) 2-bromo-2-methylbutane: 3° substrate with CH₃O⁻ (strong base + good Nu) → E2 dominant. Major = 2-methyl-2-butene (Zaitsev). Minor: 2-methyl-1-butene. Substitution minor.

NCERT 6.5
A hydrocarbon C₅H₁₀ does not react with chlorine in dark but gives a single monochloro compound C₅H₉Cl in bright sunlight. Identify the hydrocarbon.
Show Solution

Analysis:

• C₅H₁₀ has 1 double bond (or 1 ring) — degree of unsaturation = 1.

• No reaction with Cl₂ in dark → alkene (would react with Cl₂ even in dark) — so it must be a cycloalkane!

• Single monochloro compound in sunlight (free radical) → all H atoms equivalent → high symmetry.

Candidate: Cyclopentane (C₅H₁₀). All 10 H atoms are equivalent → only one monochloro product: chlorocyclopentane.

Answer: Cyclopentane

NCERT 6.6
What are the IUPAC names of the following: (a) Ph-CH₂Cl, (b) Ph-CHCl-CH₃, (c) CH₂=CH-CH₂-Br, (d) CH₂=CH-CHCl-CH₂Br?
Show Solution

(a) Ph-CH₂Cl: chloromethylbenzene (benzyl chloride)

(b) Ph-CHCl-CH₃: (1-chloroethyl)benzene

(c) CH₂=CH-CH₂-Br: 3-bromoprop-1-ene (allyl bromide)

(d) CH₂=CH-CHCl-CH₂Br: 1-bromo-3-chlorobut-3-ene — wait, numbering from end closer to double bond. Actually CH₂=CH-CHCl-CH₂Br — numbering starts at CH₂= (C1), CH (C2), CHCl (C3), CH₂Br (C4). So: 1-bromo-3-chlorobut-3-ene → no, this is wrong. Let's renumber: right side gives lower locant for halogens? Chain: CH₂=CH-CHCl-CH₂Br. Numbering: C1 = CH₂ (double bond end, gives C2 to CH), C3 = CHCl, C4 = CH₂Br → 1-bromo-3-chlorobut-3-ene? No — double bond gets priority: C1=C2 must be double bond. So: 1-bromo-3-chlorobut-3-ene.

Actually correct answer: numbering from left so double bond gets position 1: CH₂=CH-CHCl-CH₂Br → 1-bromo-3-chlorobut-3-ene is wrong (double bond is at 1-2, not 3). Correct: 1-bromo-3-chlorobut-3-ene → 1-bromo-3-chlorobut-3-ene is not right. Let me redo: C1=CH₂, C2=CH, C3=CHCl, C4=CH₂Br. Double bond is C1=C2. So locants: 1-bromo... no wait, Br is on C4. From C1 numbering: 4-bromo-3-chlorobut-1-ene. But numbering from C4: 1-bromo-3-chlorobut-3-ene? No — the double bond would then be at C3-C4 which is C3=C4. Hmm.

Better: number from CH₂Br end: C1=CH₂Br, C2=CHCl, C3=CH, C4=CH₂. Double bond = C3-C4. Locants: 1-bromo-2-chlorobut-3-ene. Now double bond has lower locant (3) than other numbering (1). So first option (double bond at C1) is preferred.

Correct answer: 4-bromo-3-chlorobut-1-ene

NCERT 6.9
Predict the order of reactivity of the following compounds in SN1 and SN2 reactions: (a) primary, secondary, tertiary chlorides, (b) 1-chlorobutane, 1-bromobutane, 1-iodobutane.
Show Solution

(a) SN1 order: 3° > 2° > 1° (carbocation stability: 3° most stable due to hyperconjugation and inductive effects)

(a) SN2 order: 1° > 2° > 3° (steric hindrance: 1° least crowded → fastest SN2)

(b) SN1 and SN2 order (based on leaving group): 1-iodobutane > 1-bromobutane > 1-chlorobutane (I⁻ is better leaving group than Br⁻ than Cl⁻)

NCERT 6.12
Explain why (a) the dipole moment of chlorobenzene is lower than that of cyclohexyl chloride, (b) Grignard reagents should be prepared under anhydrous conditions.
Show Solution

(a) In chlorobenzene, the lone pair on Cl participates in resonance with the aromatic ring → C-Cl bond has partial double bond character → the C-Cl bond is shorter. But more importantly, the resonance shifts electron density into the ring → the net dipole moment is lower. In cyclohexyl chloride, no such resonance → full dipole moment of C-Cl bond.

Dipole moment: cyclohexyl chloride (~2.2 D) > chlorobenzene (~1.7 D).

(b) Grignard reagents (R-MgX) are extremely strong bases/nucleophiles. Water protonates them:

R-MgX + H₂O → R-H + Mg(OH)X

So they get destroyed by moisture. Must be prepared in dry ether (anhydrous solvent, excluding moisture). Also use dry glassware, dry atmosphere.

NCERT 6.15
Write the mechanism of the following reaction: n-BuBr + KOH → n-BuOH + KBr (in aqueous solution).
Show Solution

Answer: This is an SN2 reaction (primary substrate, strong nucleophile, aqueous solution):

Step 1 (slow, rate-determining): OH⁻ attacks the backside of C attached to Br.

OH⁻ + Bu-Br → [HO···C(Bu)···Br]‡ (transition state)

Step 2 (fast): Br⁻ leaves as the C-O bond forms simultaneously.

Transition state → Bu-OH + Br⁻

Key features: One-step, second-order kinetics (Rate = k[BuBr][OH⁻]), inversion of configuration (if chiral substrate), favored by strong Nu and primary substrate.

NCERT 6.20
What are the major products when 2-bromopentane is heated with alcoholic KOH? Explain.
Show Solution

Answer: Alcoholic KOH is a strong base → E2 elimination.

2-bromopentane: CH₃-CH(Br)-CH₂-CH₂-CH₃

Two β-hydrogens available (on C1 and C3):

• Remove H from C1 → 1-pentene (CH₂=CH-CH₂-CH₂-CH₃) — Hofmann product (less substituted)

• Remove H from C3 → 2-pentene (CH₃-CH=CH-CH₂-CH₃) — Zaitsev product (more substituted)

Major product: 2-pentene (Zaitsev) — more stable alkene (more alkyl substituents on C=C).

Also trans-2-pentene is more stable than cis-2-pentene (less steric strain).

NCERT 6.22
What are the environmental effects of DDT and CFCs? How can they be controlled?
Show Solution

DDT:

• Bioaccumulates in fat tissue (not metabolized)

• Biomagnifies up the food chain (higher in predators)

• Causes eggshell thinning in birds (nearly wiped out bald eagles)

• Very persistent in the environment

• Banned for agricultural use by Stockholm Convention (2001)

CFCs:

• Deplete stratospheric ozone layer via Cl radical chain reaction

• One Cl atom destroys ~100,000 O₃ molecules

• Banned by Montreal Protocol (1987)

• Replaced by HFCs (which don't deplete ozone but are greenhouse gases)

Control: International treaties (Stockholm, Montreal, Kigali), phase-out of harmful compounds, use of safer alternatives (HFCs for CFCs, biopesticides for DDT).

NCERT 6.27
Give the uses of (a) chloroform, (b) iodoform, (c) carbon tetrachloride, (d) freons, (e) DDT.
Show Solution

(a) Chloroform (CHCl₃): Solvent for fats, oils, rubber, resins, alkaloids. Historically as anesthetic (now banned). Precursor to CFC-22.

(b) Iodoform (CHI₃): Antiseptic (yellow powder — old medical use). Now used as a laboratory reagent (test for methyl ketones).

(c) Carbon tetrachloride (CCl₄): Fire extinguishers (Pyrene), solvent for fats/oils/resins. Banned due to ozone depletion.

(d) Freons (CFCs): Refrigerants, propellants in aerosol sprays, blowing agents for foams. Banned by Montreal Protocol due to ozone depletion.

(e) DDT: Powerful insecticide — kills mosquitoes (malaria), lice (typhus). Banned for agriculture due to bioaccumulation but still WHO-approved for malaria control in some regions.

Quick Reference

📐 Reactions & Facts Sheet

Chapter 6 — Key Reactions & Facts

From Alcohol + HX
R-OH + HX → R-X + H₂O
Using SOCl₂
R-OH + SOCl₂ → R-Cl + SO₂ + HCl
Using PCl₅
R-OH + PCl₅ → R-Cl + POCl₃ + HCl
Free Radical Halogenation
R-H + X₂ (UV) → R-X + HX
Markovnikov Addition
H adds to C with more H
Finkelstein Reaction
R-X + NaI (dry acetone) → R-I + NaX
Swarts Reaction
R-X + AgF → R-F + AgX
SN2 Rate Law
Rate = k[R-X][Nu⁻]
SN1 Rate Law
Rate = k[R-X]
Grignard Formation
R-X + Mg (dry ether) → R-MgX
Wurtz-Fittig
Ar-X + R-X + 2Na → Ar-R + 2NaX
Fittig Reaction
2Ar-X + 2Na → Ar-Ar + 2NaX
Sandmeyer Reaction
Ar-N₂⁺Cl⁻ + Cu₂Cl₂/HCl → Ar-Cl
Dow Process
Ph-Cl + NaOH (300°C, 300 atm) → Ph-OH
DDT Formula
(p-ClC₆H₄)₂CHCCl₃
Freon-12
CCl₂F₂ (CFC-12)

Reactivity Orders (Must Memorize)

Leaving group I⁻ > Br⁻ > Cl⁻ > F⁻ I⁻ weakest base, best leaving
SN2 substrate 1° > 2° > 3° Less steric hindrance
SN1 substrate 3° > 2° > 1° Carbocation stability
E2 substrate 3° > 2° > 1° Elimination favored
C-X bond strength C-F > C-Cl > C-Br > C-I F strongest, I weakest
Haloalkane boiling point R-I > R-Br > R-Cl > R-F Heavier halogen = higher BP
Reactivity to Nu sub Allyl/Benzyl > 1° > 2° > 3° > vinyl/aryl Resonance effects
HX reactivity with alcohol HI > HBr > HCl > HF Strongest acid reacts fastest

📖 Notation Key

R-X Alkyl halide (haloalkane)
Ar-X Aryl halide (haloarene)
Nu⁻ Nucleophile
SN1 Substitution, unimolecular
SN2 Substitution, bimolecular
E1 Elimination, unimolecular
E2 Elimination, bimolecular
CFC Chlorofluorocarbon
HFC Hydrofluorocarbon (CFC replacement)
DDT Dichlorodiphenyltrichloroethane
t-BuOK Potassium tert-butoxide (bulky base)
One-Page Revision

📌 Chapter Summary

Everything You Need to Remember

  1. Haloalkanes (R-X): sp³ C. Haloarenes (Ar-X): sp² C. Allylic/benzylic (very reactive), vinylic/aryl (unreactive).
  2. Classification: 1°/2°/3° (haloalkanes), mono/di/tri/poly (by halogen count).
  3. IUPAC names: halo- prefix + alkane/benzene. Prefixes alphabetical. Halogens are substituents.
  4. C-X bond: Polar (C δ+, X δ−). Reactivity: R-I > R-Br > R-Cl > R-F (weaker bond = better leaving).
  5. Preparation: Alcohol + HX/PCl₃/PCl₅/SOCl₂; free radical halogenation; addition to alkene; Finkelstein (iodides); Swarts (fluorides); Sandmeyer (haloarenes).
  6. Physical: Higher halogens = higher BP/MP/density. Branching decreases BP/MP. Only slightly soluble in water.
  7. SN2: 1 step, second-order, inversion, favored by 1° + strong Nu + aprotic.
  8. SN1: 2 steps via carbocation, first-order, racemic, favored by 3° + weak Nu + protic.
  9. E1: carbocation, 2 steps, first-order, weak base.
  10. E2: concerted, 1 step, second-order, strong base.
  11. Zaitsev's rule: More substituted alkene (more stable) for small bases. Hofmann product for bulky bases (t-BuOK).
  12. Haloarenes unreactive to nucleophilic substitution (partial double bond, sp² C, electron-rich ring).
  13. EWG (NO₂, CN) ortho/para to X in haloarenes → much more reactive to nucleophilic substitution (Meisenheimer complex).
  14. Grignard: Ar-Br + Mg → Ar-MgBr (only works for Ar-Br, Ar-I).
  15. Chloroform: Sweet, dense liquid; toxic (phosgene); solvent; historical anesthetic.
  16. CCl₄: Fire extinguisher, solvent, ozone depleter (banned).
  17. CFCs: Refrigerants → Cl radical destroys ozone → Montreal Protocol (1987).
  18. DDT: Powerful insecticide but bioaccumulates and biomagnifies → banned (Stockholm Convention).
Exam Preparation

🎯 Common Exam Questions

2-Mark Questions

  1. Write the IUPAC name of CH₃-CH(Br)-CH(CH₃)-CH₃.
  2. Give one example of a benzylic halide and one of an allylic halide.
  3. Why is the C-I bond more reactive than C-Cl toward nucleophilic substitution?
  4. Why are haloarenes less reactive than haloalkanes toward nucleophilic substitution?
  5. What is Finkelstein reaction? Give one example.
  6. What is Swarts reaction? Give one example.
  7. What are the products of the reaction between 1-bromopropane and KOH in aqueous vs alcoholic solution?

3-Mark Questions

  1. Explain why Grignard reagents should be prepared under anhydrous conditions.
  2. Differentiate between SN1 and SN2 reactions with examples.
  3. Write the mechanism of the SN2 reaction of 1-bromopropane with OH⁻.
  4. Why does the dipole moment of chlorobenzene differ from that of cyclohexyl chloride?
  5. What is Zaitsev's rule? Give one example where it predicts the major product.
  6. Distinguish between SN2 and E2 reactions in terms of substrate and conditions.
  7. Give any three uses of chloroform.

5-Mark Questions

  1. Discuss the mechanism of SN1 and SN2 reactions. Explain the factors that favor each.
  2. What are CFCs? How do they deplete the ozone layer? What is the Montreal Protocol?
  3. What are the environmental effects of DDT? Why is it banned?
  4. Discuss the physical properties of haloalkanes with respect to boiling point, solubility, and density.
  5. Why are haloarenes less reactive to nucleophilic substitution? Give examples of exceptions with electron-withdrawing groups.
  6. Write the major products and mechanisms for the reaction of (a) 1-bromopropane with NaOH (aq), (b) t-butyl bromide with H₂O, (c) 2-bromobutane with KOH (alcoholic).
Test Yourself

✍️ MCQ Practice

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New Pattern

🎯 Assertion–Reason

(A) Both true, R explains A. (B) Both true, R does NOT explain A. (C) A true, R false. (D) A false, R true.

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Quick Revision

⚡ Formula Flashcards

All key reactions & facts at one place — perfect for quick revision before exams.

Leaving Group Order
I⁻ > Br⁻ > Cl⁻ > F⁻
SN2 Substrate Order
1° > 2° > 3°
SN1 Substrate Order
3° > 2° > 1°
SN2 Stereochemistry
Inversion (Walden)
SN1 Stereochemistry
Racemic mixture
SN1 Rate Law
Rate = k[R-X]
SN2 Rate Law
Rate = k[R-X][Nu⁻]
Finkelstein Reaction
R-X + NaI → R-I
Swarts Reaction
R-X + AgF → R-F
Grignard Formation
R-X + Mg (dry ether) → R-MgX
Dow Process
Ph-Cl + NaOH (300°C, 300 atm) → Ph-OH
Zaitsev's Rule
More substituted alkene favored